Thx,

is complex example

if i understand all the job i done in this section :

<ContentControl.ContentTemplate>
<DataTemplate>
<StackPanel Orientation="Horizontal">
<TextBlock Text="{Binding}"/>
<TextBlock Text=" SOME CUSTOM COLUMN TEXTTTTT"/>
</StackPanel>
</DataTemplate>
</ContentControl.ContentTemplate>

i  wan't to hard code the Text  but something like that

<TextBlock Text="{Binding propertyName1}"/>

<TextBlock Text="{Binding propertyName2}"/>

<TextBlock Text="{Binding propertyName3}"/>

How i can acomplish this... an example please.

thx

I want to do this by configuring  a ColumnTemplate to have more control on each property... example

i want to display a [A-136] in bold style and the date in italic style with different color.

so i want to achieve this behavior without the need to format a string.

i want an example to do this behavior.

thx

Hello Michel,

With the current implementation of the sample project, the styles applied to the PivotColumnHeaderCellControl and PivotRowHeaderCellControl will be applied to any of that element type that exist in the XamPivotGrid. If you are looking to only apply this to certain columns, I would recommend looking at giving these styles an x:Key. Doing this will allow you to retrieve them in code, and then you can apply that given style to the XamPivotGrid.GridLayout.Columns[index].HeaderCellStyle property. This would allow you to essentially define this “ColumnTemplate” that you are looking to achieve. For example, if you were to move the PivotColumnHeaderCellControl style in the sample project I had provided you to the Application.Resources section in your App.xaml and give it an x:Key of “myColumnHeaderStyle”, you could retrieve it and apply it like so, where “pivot” is the XamPivotGrid:

Style style = Application.Resources[“myColumnHeaderStyle”] as Style;
pivot.GridLayout.Columns[0].HeaderCellStyle = style;

Once you have done this, you will need a separate way of formatting the string that you wish to show in the header, which of course can be broken up by multiple elements existing in the ContentControl.ContentTemplate as shown in the sample I attached. There does not exist a way to get back to the underlying data item from the PivotColumn/RowHeaderCellControl, though, and so you will very likely have to query your underlying data source in order to get the information needed to format the different pieces of your “column template” in this case.

As an example of how you could do this, you could perhaps use a binding to your PivotColumn/RowHeadeCellControl. This element has a Cell property that will contain either the PivotColumnHeaderCell or the PivotRowHeaderCell that is represented by the cell control. Both of these elements have information about the Member, Row, and Column that they represent, which you may be able to use against your data source to query it and find the data item(s) that are represented by that column or row header. Perhaps to do this, you could use a converter in your binding to the PivotRowHeaderCell or PivotColumnHeaderCell. This binding could look like the following in your ContentControl.ContentTemplate:

<DataTemplate>
  <TextBlock Text=”{Binding RelativeSource={RelativeSource AncestorType={x:Type ig:PivotColumnHeaderCellControl}}, Path=Cell, Converter={StaticResource converterKey}” />
</DataTemplate>

In this case, “converterKey” would be the x:Key of an IValueConverter instance that you bring in as a resource. This converter would look at the PivotRowHeaderCell/PivotColumnHeaderCell, query your underlying data source to your Olap data source being used for the XamPivotGrid, and return a suitable string for your TextBlock.Text property that you place in your header based on the information that your data source returns.

I hope this helps. Please let me know if you have any other questions or concerns on this matter.

Thx

   Can you put it in the example you sent later 

Appreciated.

Thank you very Much !