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Manfred
65
Problem using WebTab with Scriptmanager
posted

Hi,
I have made a simple WebAppl with an Ultrawebtab and 3 Pages.
The 3 Pages are called with the Eventhandler:
        void UltraWebTab1_TabClick(object sender, Infragistics.WebUI.UltraWebTab.WebTabEvent e){
            switch (e.Tab.Key){
                case "0": e.Tab.ContentPane.TargetUrl = "Page1.aspx"; break;
                case "1": e.Tab.ContentPane.TargetUrl = "Page2.aspx"; break;
                case "2": e.Tab.ContentPane.TargetUrl = "Page3.aspx"; break;}}
So far it works well.

But when I add a scriptmanager to the 3 pages, I got an error:
 in line 997 of MicrosoftAjaxWebForms.debug.js:
  if (!this._postBackSettings.async) {
Errormessage: 'this._postBackSettings.async' is null or not an object
Any help?

Enviroment: MSVS2008 C# Framework 3.5 and Infragistics35.WebUI.UltraWebTab.v8.1

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  • 5
    posted

    I had the same issue.  It would only occur if you navigate to a tab and then navigate away from the tab without clicking on any control in the tab.  Let me reword that.  If you goto and then leave a tab without clicking on any of the controls the problem occurs.  The way I fixed this was with the following code.

     

    <button id="oButton" style="display:none" onclick="this.innerText='I have been clicked!'">Button</button>
    <script type="text/javascript" language="javascript">
    document.getElementById('oButton').fireEvent("onclick");
    </script>

    or here is a version of the same thing that I now use in a base page class so that it works for all my pages. 

    string script = @"<script type=""text/javascript"" language=""javascript"">
    Sys.Application.add_load(DoLoad {
    // This is here to get rid of an odd bug in the Ultra tab control from Infragistics.
    // If you don't click on the page you navigate to before navigating away from it, a javascript error will be thrown
    var form = document.forms[0];
    var myMsg = ""I have been clicked"";
    var myButt = document.createElement(""button"");
    myButt.id = ""oButton1"";
    myButt.style.display = ""none"";
    myButt.onclick = ""this.innerText='I have been clicked'"";
    form.appendChild(myButt);
    myButt.fireEvent(""onclick"");
    }
    </script>"    ;

     

    ScriptManager.RegisterStartupScript(this, this.GetType(), Guid.NewGuid().ToString(), script, false);

     

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